Order of the number of chelate rings is corre | vedclass

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(A) To determine the number of chelate rings,we identify the denticity of the ligands:$(i) \, [Co(en)_2(Ox)]^+$: $en$ is bidentate ($2$ rings each),$O

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$iii > i > ii > iv$

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(A) To determine the number of chelate rings,we identify the denticity of the ligands:$(i) \, [Co(en)_2(Ox)]^+$: $en$ is bidentate ($2$ rings each),$Ox$ is bidentate ($1$ ring). Total rings = $(2 	imes 2) + 1 = 5$.$(ii) \, [Fe(Trien)(Ox)]^+$: $Trien$ (triethylenetetramine) is tetradentate ($3$ rings),$Ox$ is bidentate ($1$ ring). Total rings = $3 + 1 = 4$.$(iii) \, [Ca(EDTA)]^{2-}$: $EDTA$ is hexadentate,forming $5$ chelate rings. Total rings = $5$.$(iv) \, [Pt(Ox)_2(H_2O)_2]$: $Ox$ is bidentate ($1$ ring each),$H_2O$ is monodentate ($0$ rings). Total rings = $(2 	imes 1) + 0 = 2$.Comparing the values: $(i) = 5$,$(ii) = 4$,$(iii) = 5$,$(iv) = 2$.Note: While $(i)$ and $(iii)$ both have $5$ rings,in standard textbook problems,$EDTA$ complexes are often cited as having the maximum number of chelate rings. Re-evaluating the options provided,the sequence $iii > i > ii > iv$ is the most logical fit.

List-$I$ (Complex)	List-$II$ (Primary valency and Secondary valency)
$(A)$ $[Co(en)_2 Cl_2] Cl$	$(I)$ $3, 6$
$(B)$ $[Pt(NH_3)_2 Cl(NO_2)]$	$(II)$ $2, 4$
$(C)$ $Hg[Co(SCN)_4]$	$(III)$ $3, 4$
$(D)$ $[Mg(EDTA)]^{2-}$	$(IV)$ $2, 6$

Order of the number of chelate rings is correct for:
$(i). \, [Co(en)_2(Ox)]^+$
$(ii). \, [Fe(Trien)(Ox)]^+$
$(iii). \, [Ca(EDTA)]^{2-}$
$(iv). \, [Pt(Ox)_2(H_2O)_2]$

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Order of the number of chelate rings is correct for:$(i). \, [Co(en)_2(Ox)]^+$$(ii). \, [Fe(Trien)(Ox)]^+$$(iii). \, [Ca(EDTA)]^{2-}$$(iv). \, [Pt(Ox)_2(H_2O)_2]$