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(B) $1)$ The given compounds are coordination isomers. The first complex $[Cr(NH_3)_6][Cr(NO_2)_6]$ consists of a $3+:3-$ electrolyte system,while the

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Measurement of molar conductance

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(B) $1)$ The given compounds are coordination isomers. The first complex $[Cr(NH_3)_6][Cr(NO_2)_6]$ consists of a $3+:3-$ electrolyte system,while the second complex $[Cr(NH_3)_4(NO_2)_2][Cr(NH_3)_2(NO_2)_4]$ consists of a $1+:1-$ electrolyte system.$2)$ Molar conductance $(\Lambda_m)$ depends on the number of ions and the magnitude of the charge on the ions. Since the charge on the complex ions differs between the two isomers ($3$ vs $1$),their molar conductances will be significantly different.$3)$ Magnetic moments depend on the number of unpaired electrons. Since both complexes contain $Cr^{3+}$ ions in an octahedral field,they have the same number of unpaired electrons and similar magnetic properties.$4)$ Therefore,measurement of molar conductance is the most effective method to distinguish these isomers.

List-$I$	List-$II$
$A$. $[Fe(H_2O)_6]^{2+}$	$P$. $0$
$B$. $[Fe(H_2O)_6]^{3+}$	$Q$. $1$
$C$. $[Fe(CN)_6]^{4-}$	$R$. $2$
$D$. $[Fe(CN)_6]^{3-}$	$S$. $4$
$E$. $[Ni(H_2O)_4]^{2+}$	$T$. $5$

Other than $X$-ray diffraction,how can the following pairs of isomers be distinguished from one another?
$[Cr(NH_3)_6][Cr(NO_2)_6]$ and $[Cr(NH_3)_4(NO_2)_2][Cr(NH_3)_2(NO_2)_4]$

Similar Questions

The total number of possible isomers of the complex compound $[Cu(NH_3)_4] [PtCl_4]$ is:

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List-$I$ List-$II$

$A$. $[Fe(H_2O)_6]^{2+}$ $P$. $0$

$B$. $[Fe(H_2O)_6]^{3+}$ $Q$. $1$

$C$. $[Fe(CN)_6]^{4-}$ $R$. $2$

$D$. $[Fe(CN)_6]^{3-}$ $S$. $4$

$E$. $[Ni(H_2O)_4]^{2+}$ $T$. $5$

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Other than $X$-ray diffraction,how can the following pairs of isomers be distinguished from one another?$[Cr(NH_3)_6][Cr(NO_2)_6]$ and $[Cr(NH_3)_4(NO_2)_2][Cr(NH_3)_2(NO_2)_4]$