Out of $H_2O$ and $H_2S$,which one has a higher bond angle and why?

  • A
    $H_2O$ due to higher electronegativity of $O$.
  • B
    $H_2S$ due to larger size of $S$.
  • C
    $H_2O$ due to $sp^3$ hybridization and smaller size of $O$.
  • D
    $H_2S$ due to $sp^3$ hybridization.

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