Out of 450 students of a school,325 play foot | vedclass

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(C) Total number of students in the school $= 450$.Number of students who play neither football nor cricket $= 50$.Therefore,the number of students wh

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(C) Total number of students in the school $= 450$.Number of students who play neither football nor cricket $= 50$.Therefore,the number of students who play at least one game (either football or cricket) is $n(F \cup C) = 450 - 50 = 400$.Given that the number of students who play football is $n(F) = 325$ and the number of students who play cricket is $n(C) = 175$.Using the set theory formula: $n(F \cup C) = n(F) + n(C) - n(F \cap C)$.Substituting the values: $400 = 325 + 175 - n(F \cap C)$.$400 = 500 - n(F \cap C)$.$n(F \cap C) = 500 - 400 = 100$.Thus,$100$ students play both football and cricket.

Out of $450$ students of a school,$325$ play football,$175$ play cricket and $50$ neither play football nor cricket. How many students play both football and cricket?

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