Out of 10 white,9 black and 7 red balls,the n | vedclass

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(C) To select one or more balls from a collection of identical items of different types,we use the formula $(n_1 + 1)(n_2 + 1)(n_3 + 1) - 1$,where $n_

Vedclass · Accepted Answer

$879$

Vedclass · Answer

(C) To select one or more balls from a collection of identical items of different types,we use the formula $(n_1 + 1)(n_2 + 1)(n_3 + 1) - 1$,where $n_1, n_2, n_3$ are the number of balls of each color.Here,$n_1 = 10$ (white),$n_2 = 9$ (black),and $n_3 = 7$ (red).The total number of ways to select one or more balls is given by $(10 + 1)(9 + 1)(7 + 1) - 1$.$= 11 	imes 10 	imes 8 - 1$.$= 880 - 1 = 879$.Thus,the total number of ways is $879$.

Out of $10$ white,$9$ black and $7$ red balls,the number of ways in which selection of one or more balls can be made,is

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