Out of BeF_{2}, MgF_{2}, CaF_{2}, SrF_{2},whi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The solubility of alkaline earth metal fluorides is determined by the balance between lattice energy and hydration energy.For small cations like $

Vedclass · Accepted Answer

$BeF_{2}$

Vedclass · Answer

(A) The solubility of alkaline earth metal fluorides is determined by the balance between lattice energy and hydration energy.For small cations like $Be^{2+}$,the hydration energy is significantly higher than the lattice energy,making $BeF_{2}$ highly soluble in water.As the size of the cation increases from $Be^{2+}$ to $Sr^{2+}$,the hydration energy decreases more rapidly than the lattice energy,leading to a decrease in solubility.Therefore,$BeF_{2}$ has the maximum solubility among the given compounds.

Out of $BeF_{2}, MgF_{2}, CaF_{2}, SrF_{2}$,which has maximum solubility?

Similar Questions

Property of the alkaline earth metals that increases with their atomic number is

What is slaking of lime?

Which element from the following is used for cancer treatment?

Which of the following oxides is most acidic in nature?

$A$ metal $M$ readily forms its sulphate $MSO_4$ which is water-soluble. It forms its oxide $MO$ which becomes inert on heating. It forms its insoluble hydroxide $M(OH)_2$ which is soluble in $NaOH$ solution. Then $M$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module