(A) Let the oxidation number of $N$ be $x$.In $NH_3$,the oxidation number of each $H$ atom is $+1$.The sum of oxidation numbers in a neutral molecule

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(A) Let the oxidation number of $N$ be $x$.In $NH_3$,the oxidation number of each $H$ atom is $+1$.The sum of oxidation numbers in a neutral molecule is $0$.Therefore,$x + 3(+1) = 0$.$x + 3 = 0$.$x = -3$.Thus,the oxidation number of $N$ in $NH_3$ is $-3$.