Oxidation of carbon with concentrated sulphur | vedclass

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(C) The reaction of carbon with concentrated sulphuric acid is: $C + 2H_2SO_4 \rightarrow CO_2 + 2SO_2 + 2H_2O$. The oxides formed are $CO_2$,$SO_2$,a

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$sp, sp^3$

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(C) The reaction of carbon with concentrated sulphuric acid is: $C + 2H_2SO_4 \rightarrow CO_2 + 2SO_2 + 2H_2O$. The oxides formed are $CO_2$,$SO_2$,and $H_2O$. In $CO_2$ $(O=C=O)$,the carbon atom is bonded to two oxygen atoms with no lone pairs,resulting in $sp$ hybridisation. In $H_2O$ $(H-O-H)$,the oxygen atom is bonded to two hydrogen atoms and has two lone pairs,resulting in $sp^3$ hybridisation. Therefore,the hybridisation of the central atoms in the oxides of $C$ and $H$ (which is $O$ in $H_2O$) are $sp$ and $sp^3$ respectively.

Oxidation of carbon with concentrated sulphuric acid gives the corresponding oxides of $C, S$ and $H$. The hybridisation of the central atoms in the oxides of $C$ and $H$ are respectively.

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