Oxidation of cyclohexene in the presence of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The oxidation of $cyclohexene$ with a strong oxidizing agent like acidic $KMnO_4$ results in the cleavage of the double bond and the formation of

Vedclass · Accepted Answer

adipic acid

Vedclass · Answer

(B) The oxidation of $cyclohexene$ with a strong oxidizing agent like acidic $KMnO_4$ results in the cleavage of the double bond and the formation of a dicarboxylic acid.Specifically,$cyclohexene$ $(C_6H_{10})$ undergoes oxidative cleavage to form $adipic$ $acid$ $(HOOC-(CH_2)_4-COOH)$,which is a $6$-carbon dicarboxylic acid.The chemical reaction is as follows:$3C_6H_{10} + 8KMnO_4 + 4H_2O \rightarrow 3HOOC(CH_2)_4COOH + 8KOH + 8MnO_2$Thus,the product formed is $adipic$ $acid$.

Oxidation of cyclohexene in the presence of acidic potassium permanganate leads to:

Similar Questions

The metal used for the de-bromination reaction of $1, 2$-dibromoethane is:

One mole of alkene $\underline{X}$ on ozonolysis gave one mole of acetaldehyde and one mole of acetone. The $IUPAC$ name of $\underline{X}$ is

Identify the missing product in the following reaction:
$CH_3CH_2OH \xrightarrow[443 \ K]{H_2SO_4} (?)$

What is $A$ in the following reaction?
$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow A$

Which of the following reacts with $KMnO_4$ but does not react with $AgNO_3$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module