(B) Let the oxidation state of $Fe$ be $x$. In $K_3[Fe(CN)_6]$,the oxidation state of $K$ is $+1$ and the oxidation state of $CN^-$ is $-1$. The sum o

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(B) Let the oxidation state of $Fe$ be $x$. In $K_3[Fe(CN)_6]$,the oxidation state of $K$ is $+1$ and the oxidation state of $CN^-$ is $-1$. The sum of oxidation states in a neutral complex is $0$. $3 \times (+1) + x + 6 \times (-1) = 0$ $3 + x - 6 = 0$ $x - 3 = 0$ $x = +3$. Therefore,the oxidation state of $Fe$ is $+3$.