Oxidation state of S in H_2S_2O_8 is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the structure of $H_2S_2O_8$ (peroxodisulphuric acid), there is a peroxide linkage $(-O-O-)$. Two oxygen atoms are involved in the peroxide lin

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) In the structure of $H_2S_2O_8$ (peroxodisulphuric acid), there is a peroxide linkage $(-O-O-)$. Two oxygen atoms are involved in the peroxide linkage, each having an oxidation state of $-1$. The remaining $6$ oxygen atoms have an oxidation state of $-2$. Let the oxidation state of $S$ be $x$. Applying the oxidation state rule: $2(+1) + 2(x) + 2(-1) + 6(-2) = 0$. $2 + 2x - 2 - 12 = 0$. $2x = 12$. $x = +6$.

Oxidation state of $S$ in $H_2S_2O_8$ is

Similar Questions

What is the oxidation number of oxygen in a superoxide ion?

Amongst the following,identify the species with an atom in $+6$ oxidation state.

The oxidation states of $S$ in $H_2S_2O_7$ are:

What is the oxidation state of oxygen in $OF_2$ and in $KO_2$ respectively?

Which one is an incorrect statement?

Vedclass Test Series

Exam Paper Generator

Online Exam Module