The oxidation state of elemental carbon is:
- A$0$
- B$1$
- C$2$
- D$3$
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The oxidation state of $Cr$ in $K_{2}Cr_{2}O_{7}$ is
Oxidation number of $P$ in $Mg_2P_2O_7$ is
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View SolutionMatch the following compounds with the oxidation number of the central atom (or specific atom in question):
Compound Oxidation number $1$. $C_6H_{12}O_6$ (Carbon) $a$. $+1$ $2$. $CCl_4$ (Carbon) $b$. $0$ $3$. $NH_4Cl$ (Nitrogen) $c$. $+4$ $4$. $Ba(H_2PO_2)_2$ (Phosphorus) $d$. $-3$
| Compound | Oxidation number |
| $1$. $C_6H_{12}O_6$ (Carbon) | $a$. $+1$ |
| $2$. $CCl_4$ (Carbon) | $b$. $0$ |
| $3$. $NH_4Cl$ (Nitrogen) | $c$. $+4$ |
| $4$. $Ba(H_2PO_2)_2$ (Phosphorus) | $d$. $-3$ |
Medium
View SolutionIn which of the following compounds,an element exhibits two different oxidation states?
In $Na_2S_4O_6$,the oxidation number of $S$ is
Easy
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