The percentage of (G + C) in a DNA molecule i | vedclass

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Question

(A) In a $DNA$ molecule,the total nitrogenous bases consist of Adenine $(A)$,Guanine $(G)$,Thymine $(T)$,and Cytosine $(C)$.To calculate the percentag

Vedclass · Accepted Answer

$\frac{G + C}{A + G + T + C} 	imes 100$

Vedclass · Answer

(A) In a $DNA$ molecule,the total nitrogenous bases consist of Adenine $(A)$,Guanine $(G)$,Thymine $(T)$,and Cytosine $(C)$.To calculate the percentage of a specific base pair composition like $(G + C)$,we divide the sum of Guanine and Cytosine by the total number of nitrogenous bases $(A + G + T + C)$ and multiply by $100$.Therefore,the formula is $\frac{G + C}{A + G + T + C} 	imes 100$.Thus,option $(A)$ is the correct answer.

The percentage of $(G + C)$ in a $DNA$ molecule is given by:

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