Peroxide effect is observed with the addition of $HBr$ but not with the addition of $HI$ to unsymmetrical alkene because

  • A
    $H-I$ bond is stronger than $H-Br$ and is not cleaved by the free radical
  • B
    $H-I$ bond is weaker than $H-Br$ bond so that iodine free radicals combine to form iodine molecules
  • C
    Bond strength of $HI$ and $HBr$ are same but free radicals are formed in $HBr$
  • D
    All of the above

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Similar Questions

In the following reaction,$A$ and $B$ respectively are
$A \xrightarrow{HBr} C_2H_5Br \xrightarrow{B} A$

$A$ gas decolourises Bayer's reagent but does not react with Tollen's reagent. This gas is:

Alkenes convert into alcohols by:

The stereochemistry of the product formed in the following reaction is:

Given below are two statements $:$
Statement $I :$ Ozonolysis followed by treatment with $Zn, H_2O$ of $cis-2-butene$ gives ethanal.
Statement $II :$ The product obtained by ozonolysis followed by treatment with $Zn, H_2O$ of $3,6-dimethyloct-4-ene$ has no chiral carbon atom.
In the light of the above statements,choose the correct answer from the options given below.

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