Philip, Tom, and Brad start jogging around a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To find the time when they meet again at the starting point, we need to calculate the Least Common Multiple $(LCM)$ of the time taken by each pers

Vedclass · Accepted Answer

$16\, 	ext{minutes } 30\, 	ext{seconds}$

Vedclass · Answer

(C) To find the time when they meet again at the starting point, we need to calculate the Least Common Multiple $(LCM)$ of the time taken by each person to complete one round.The times are $18\, 	ext{seconds}$, $22\, 	ext{seconds}$, and $30\, 	ext{seconds}$.Prime factorization:$18 = 2 	imes 3^2$$22 = 2 	imes 11$$30 = 2 	imes 3 	imes 5$$LCM(18, 22, 30) = 2^1 	imes 3^2 	imes 5^1 	imes 11^1 = 2 	imes 9 	imes 5 	imes 11 = 990\, 	ext{seconds}$.Now, convert $990\, 	ext{seconds}$ into minutes:$990 / 60 = 16.5\, 	ext{minutes}$.$0.5\, 	ext{minutes} = 0.5 	imes 60 = 30\, 	ext{seconds}$.Therefore, they will meet again at the starting point after $16\, 	ext{minutes and } 30\, 	ext{seconds}$.

Philip, Tom, and Brad start jogging around a circular field and complete a single round in $18\, \text{seconds}$, $22\, \text{seconds}$, and $30\, \text{seconds}$, respectively. In how much time will they meet again at the starting point?

Similar Questions

What will be the least number which when doubled will be exactly divisible by $12, 18, 21$ and $30$?

What is the least value that should be added to $1812$ to make it divisible by $7, 11,$ and $14$?

In a school,$391$ boys and $323$ girls have been divided into the largest possible equal classes,so that each class of boys numbers the same as each class of girls. What is the number of classes?

The $H.C.F.$ of two numbers is $11$ and their $L.C.M.$ is $693$. If one of the numbers is $77$,find the other.

What is the least number which,when divided by $5, 6, 7, 8$ gives the remainder $3$ but is divisible by $9$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module