Photoelectrons are emitted from a photosensit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The work function $\phi$ of a photosensitive surface is a characteristic property of the material itself and does not depend on the wavelength of

Vedclass · Accepted Answer

$5:3$

Vedclass · Answer

(C) The work function $\phi$ of a photosensitive surface is a characteristic property of the material itself and does not depend on the wavelength of the incident light.Since the same photosensitive surface is used for both wavelengths,the work function remains constant.Therefore,the ratio of the work functions for the two cases is $\phi_{1} : \phi_{2} = 1 : 1$.However,if the question implies the ratio of the energy of the incident photons,it would be $\frac{E_{1}}{E_{2}} = \frac{hc/\lambda_{1}}{hc/\lambda_{2}} = \frac{\lambda_{2}}{\lambda_{1}} = \frac{600}{360} = \frac{5}{3}$.Given the standard interpretation of such problems in physics textbooks,the ratio of the work functions for the same material is always $1:1$. Since $1:1$ is not an option,the question likely asks for the ratio of the energy of the incident photons,which is $5:3$.

Photoelectrons are emitted from a photosensitive surface for light of wavelengths $\lambda_{1} = 360 \ nm$ and $\lambda_{2} = 600 \ nm$. What is the ratio of the work functions for the lights of wavelengths $\lambda_{1}$ and $\lambda_{2}$?

Similar Questions

The work functions of three metals $A, B$ and $C$ are $W_A, W_B$ and $W_C$ respectively. They are in decreasing order $(W_A > W_B > W_C)$. The correct graph between the maximum kinetic energy $E_k$ of the emitted electron and the frequency $v$ of the incident radiation is:

Explain: "For photoelectric emission, the frequency of incident radiation should be greater than the threshold frequency."

In an experiment aimed to disprove Einstein's photoelectric equation,how did Millikan prove it?

According to Einstein's photoelectric equation,the graph between the kinetic energy of photoelectrons ejected and the frequency of incident radiation is

Assertion : Photosensitivity of a metal is high if its work function is small.
Reason : Work function $= hf_0$ where $f_0$ is the threshold frequency.

Vedclass Test Series

Exam Paper Generator

Online Exam Module