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Question

(B) The conductivity of an electrolytic solution depends on the number of ions produced upon dissociation.$1$. $K_2[PtCl_6] \rightarrow 2K^+ + [PtCl_6

Vedclass · Accepted Answer

$[Co(NH_3)_3(NO_2)_3]$

Vedclass · Answer

(B) The conductivity of an electrolytic solution depends on the number of ions produced upon dissociation.$1$. $K_2[PtCl_6] \rightarrow 2K^+ + [PtCl_6]^{2-}$ ($3$ ions)$2$. $[Co(NH_3)_3(NO_2)_3] \rightarrow$ No ions (non-ionizable as it is a neutral complex)$3$. $K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}$ ($5$ ions)$4$. $[Cu(NH_3)_4]SO_4 \rightarrow [Cu(NH_3)_4]^{2+} + SO_4^{2-}$ ($2$ ions)Since $[Co(NH_3)_3(NO_2)_3]$ does not produce any ions in solution,it is a poor electrolytic conductor.

Pick out from the following complex compounds,a poor electrolytic conductor in solution.

Similar Questions

Which of the following does not react with $AgCl$?

Aqueous copper sulphate solution (blue in colour) gives:
$(i)$ a green precipitate with aqueous potassium fluoride,and
$(ii)$ a bright green solution with aqueous potassium chloride
Explain these experimental results.

Which of the following is the most stable complex ion?

Arrange the following complexes in the correct increasing order of their electrical conductivity in aqueous solution:
$(I) [Pt(NH_3)_6]Cl_4$
$(II) [Cr(NH_3)_6]Cl_3$
$(III) [Co(NH_3)_4Cl_2]Cl$
$(IV) K_2[PtCl_6]$

Select the option containing the correct order of the given parameter.

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