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Considering the ground state of $Cr$ atom $(Z = 24)$,the number of electrons associated with azimuthal quantum numbers $l = 1$ and $l = 2$ are,respectively:

An electron has a magnetic quantum number of $-3$. Its principal quantum number can be

What is the difference between $2p$ and $2s$ orbitals?

Which of the following sets of quantum numbers is not possible?

How many orbitals is/are possible with $n=3$,$l=1$ and $m_l=-1$ values?

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