Potassium carbonate cannot be prepared by the Solvay process. Why?

(N/A) The Solvay process involves the reaction of $NaCl$ with $NH_3$ and $CO_2$ to form $NaHCO_3$,which precipitates out because it is sparingly soluble in water. In the case of potassium,$KHCO_3$ is formed,but it is fairly soluble in water and does not precipitate out. Therefore,the process cannot be used to prepare $K_2CO_3$.