The potential at point A is 3 V and at point | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The potential at point $A$ is $V_A = 3 \ V$ and at point $B$ is $V_B = 7 \ V$.An electron has a negative charge $q = -e$.The potential energy of a

Vedclass · Accepted Answer

Both $A$ and $C$ are correct.

Vedclass · Answer

(D) The potential at point $A$ is $V_A = 3 \ V$ and at point $B$ is $V_B = 7 \ V$.An electron has a negative charge $q = -e$.The potential energy of an electron at any point is given by $U = qV = -eV$.Therefore,the potential energy at $A$ is $U_A = -3e \ V$ and at $B$ is $U_B = -7e \ V$.Since the electron is moving from $B$ to $A$,it is moving from a region of lower potential energy $(-7e \ V)$ to a region of higher potential energy $(-3e \ V)$.By the law of conservation of energy,$K_i + U_i = K_f + U_f$,where $K$ is kinetic energy.$K_B + U_B = K_A + U_A$$K_A = K_B + (U_B - U_A) = K_B + (-7e - (-3e)) = K_B - 4e$.For the electron to reach $A$,its kinetic energy at $A$ must be non-negative $(K_A \ge 0)$.$K_B - 4e \ge 0 \implies K_B \ge 4 \ eV$.Thus,the electron must have at least $4 \ eV$ of kinetic energy at $B$ to reach $A$. This also implies it must have some kinetic energy at $B$.

The potential at point $A$ is $3 \ V$ and at point $B$ is $7 \ V$. An electron is moving towards $A$ from $B$. Which of the following statements is correct?

Similar Questions

Charges of $1 \mu C$ are placed at each of the four corners of a square of side $2 \sqrt{2} \text{ m}$. The potential at the point of intersection of the diagonals is . . . . . . .

Three particles,each having a charge of $10\,\mu C$,are placed at the corners of an equilateral triangle of side $10\,cm$. The electrostatic potential energy of the system is.....$J$ (Given $\frac{1}{4\pi\varepsilon_0} = 9 \times 10^9\,N\cdot m^2/C^2$).

$A$ nerve fiber membrane separates two conducting fluids and maintains a constant potential difference. What is the order of this potential difference?

$A$ pellet carrying a charge of $0.5\, C$ is accelerated through a potential difference of $2,000\, V$. What is the kinetic energy attained by the pellet?

An electric dipole is placed as shown in the figure. The electric potential (in $10^2 \ V$) at point $P$ due to the dipole is ($\epsilon_0 =$ permittivity of free space and $\frac{1}{4 \pi \epsilon_0} = K$):

Vedclass Test Series

Exam Paper Generator

Online Exam Module