The potential difference across the terminals | vedclass

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(D) From the circuit diagram,we can see that the terminals of the battery are connected directly by a conducting wire (a short circuit path).Let the e

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(D) From the circuit diagram,we can see that the terminals of the battery are connected directly by a conducting wire (a short circuit path).Let the electromotive force of the battery be $E = 10 \, V$ and its internal resistance be $r = 1 \, \Omega$.The current $I$ flowing through the circuit is given by $I = \frac{E}{r} = \frac{10}{1} = 10 \, A$.The potential difference $V$ across the terminals of the battery is given by the formula $V = E - Ir$.Substituting the values,we get $V = 10 - (10 	imes 1) = 10 - 10 = 0 \, V$.Since the battery is short-circuited,the potential difference across its terminals is zero. The $4 \, \Omega$ resistor is in parallel with the short-circuit wire,so no current flows through it.

The potential difference across the terminals of the battery shown in the figure is ............ $V$. ($r$ = internal resistance of the battery)

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