Potential energy as a function of $r$ is given by $U = \frac{A}{r^{10}} - \frac{B}{r^{5}}$,where $r$ is the interatomic distance,and $A$ and $B$ are positive constants. The equilibrium distance between the two atoms will be

  • A
    $\left(\frac{A}{B}\right)^{\frac{1}{5}}$
  • B
    $\left(\frac{B}{A}\right)^{\frac{1}{5}}$
  • C
    $\left(\frac{2A}{B}\right)^{\frac{1}{5}}$
  • D
    $\left(\frac{B}{2A}\right)^{\frac{1}{5}}$

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$A$ particle is placed at the origin and a force $F = kx$ is acting on it (where $k$ is a positive constant). If $U(0) = 0$,the graph of $U(x)$ versus $x$ will be (where $U$ is the potential energy function):

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