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(B) Let the resistance of the original wire be $R$. The power generated is $H = V^2/R$.When the wire is cut into $n$ equal parts,the resistance of eac

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$n^2H$

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(B) Let the resistance of the original wire be $R$. The power generated is $H = V^2/R$.When the wire is cut into $n$ equal parts,the resistance of each part becomes $R' = R/n$.When these $n$ parts are connected in parallel,the equivalent resistance $R_{	ext{eq}}$ is given by $1/R_{	ext{eq}} = n 	imes (1/R') = n 	imes (n/R) = n^2/R$.Thus,$R_{	ext{eq}} = R/n^2$.The new power generated is $H_{	ext{total}} = V^2/R_{	ext{eq}} = V^2 / (R/n^2) = n^2 (V^2/R) = n^2 H$.

Power generated across a uniform wire connected across a supply is $H$. If the wire is cut into $n$ equal parts and all the parts are connected in parallel across the same supply,the total power generated in the wire is

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