Pradeep invested 20% more than Mohit. Mohit i | vedclass

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(A) Let the investment of Raghu be $x$.Since Mohit invested $10\%$ less than Raghu,Mohit's investment $= x - 0.10x = 0.9x$.Pradeep invested $20\%$ mor

Vedclass · Accepted Answer

$6000$

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(A) Let the investment of Raghu be $x$.Since Mohit invested $10\%$ less than Raghu,Mohit's investment $= x - 0.10x = 0.9x$.Pradeep invested $20\%$ more than Mohit,so Pradeep's investment $= 0.9x + 0.20(0.9x) = 0.9x + 0.18x = 1.08x$.The total sum of their investments is $x + 0.9x + 1.08x = 2.98x$.Given that the total sum is $₹ 17,880$,we have $2.98x = 17880$.Solving for $x$: $x = \frac{17880}{2.98} = 6000$.Therefore,Raghu invested $₹ 6000$.

Pradeep invested $20\%$ more than Mohit. Mohit invested $10\%$ less than Raghu. If the total sum of their investment is $₹ 17,880$,how much amount did Raghu invest?

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