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(C) The reaction proceeds in two main steps: $1$. Claisen-Schmidt condensation: Acetophenone reacts with $4$-methylbenzaldehyde in the presence of $Na

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(C) The reaction proceeds in two main steps: $1$. Claisen-Schmidt condensation: Acetophenone reacts with $4$-methylbenzaldehyde in the presence of $NaOH$ to form an $\alpha,\beta$-unsaturated ketone (chalcone derivative). $2$. Michael addition: The lithium enolate of cyclohexanone performs a conjugate addition (Michael addition) to the $\alpha,\beta$-unsaturated ketone formed in the first step. Following the mechanism,the enolate attacks the $\beta$-carbon of the unsaturated system. After protonation with $H_2O$,the final product is the one where the cyclohexanone ring is attached to the $\beta$-carbon of the original chalcone structure. Comparing this with the given options,the structure matches option $C$.

List-$I$	List-$II$
$A$. Grignard reagent	$1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction	$2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction	$3$. $CH_3MgX$
$D$. Wolff-Kishner reduction	$4$. $Zn-Hg / \text{conc. } HCl$
	$5$. $H_2 / Ni$

Predict the major product of the following reaction sequence:

Similar Questions

What is the major product of the following reaction?

Match the following lists:
List-$I$ List-$II$
$A$. Grignard reagent $1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction $2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction $3$. $CH_3MgX$
$D$. Wolff-Kishner reduction $4$. $Zn-Hg / \text{conc. } HCl$
$5$. $H_2 / Ni$

The following transformation can be best carried out using:

The increasing order of the rate of $HCN$ addition to the following compounds is:
$(A)\ HCHO$
$(B)\ CH_3COCH_3$
$(C)\ PhCOCH_3$
$(D)\ PhCOPh$

The reaction of $3$-bromobenzaldehyde with concentrated $NaOH$ $(50\, \%)$ yields which of the following products?

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