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Formaldehyde when treated with $KOH$ gives methanol and potassium formate. The reaction is known as

Arrange the following reagents in the correct order in which the above transformation is carried out:

In the reaction,$[X]$ will be:

$(A) Ph-CH(OH)-CHO \xrightarrow[H_2O]{HO^-} (B)$; $(A)$ and $(B)$ are isomers and isomerization is effectively carried out by a trace of base. Identify $(B)$.

Statement-$I$ :- Acetaldehyde and acetone can be distinguished by Tollen's reagent.
Statement-$II$ :- Aromatic aldehyde does not give Fehling test.

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