Preparation of alcohols from alkenes involves the electrophilic attack on alkene carbon. Explain its mechanism.

(N/A) The mechanism of acid-catalyzed hydration of an alkene to form an alcohol proceeds in three steps:
Step-$1$: Protonation of alkene to form a carbocation by electrophilic attack of hydronium ion $(H_{3}O^{+})$.
$CH_{3}-CH=CH_{2} + H_{3}O^{+} \xrightarrow{\text{slow}} CH_{3}-CH^{+}-CH_{3} + H_{2}O$
Step-$2$: Nucleophilic attack of water on the carbocation.
$CH_{3}-CH^{+}-CH_{3} + H_{2}O \xrightarrow{\text{fast}} CH_{3}-CH(OH_{2}^{+})-CH_{3}$
Step-$3$: Deprotonation to form an alcohol.
$CH_{3}-CH(OH_{2}^{+})-CH_{3} + H_{2}O \xrightarrow{\text{fast}} CH_{3}-CH(OH)-CH_{3} + H_{3}O^{+}$