Pressure at the bottom of a tank of water is | vedclass

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(B) The initial pressure at the bottom of the tank is given by $P_{bottom} = P + h \rho g = 3P$,where $h$ is the initial height of the water column.Fr

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$13P/5$

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(B) The initial pressure at the bottom of the tank is given by $P_{bottom} = P + h \rho g = 3P$,where $h$ is the initial height of the water column.From this,we get $h \rho g = 2P$.When the water level is lowered by one-fifth,the new height of the water column becomes $h' = h - \frac{h}{5} = \frac{4h}{5}$.The new pressure at the bottom is $P' = P + h' \rho g$.Substituting the value of $h'$,we get $P' = P + \left(\frac{4h}{5}\right) \rho g = P + \frac{4}{5}(h \rho g)$.Substituting $h \rho g = 2P$ into the equation,we get $P' = P + \frac{4}{5}(2P) = P + \frac{8P}{5} = \frac{13P}{5}$.

Pressure at the bottom of a tank of water is $3P$,where $P$ is atmospheric pressure. If water is drawn out till the level of water is lowered by one-fifth,then the pressure at the bottom of the tank is

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