In the given reaction,product B is:Cyclohexan | vedclass

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(A) $1$. The reaction of cyclohexane with $Br_2$ in the presence of $h
u$ ($UV$ light) is a free-radical substitution reaction,which produces bromocy

Vedclass · Accepted Answer

Bicyclohexyl

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(A) $1$. The reaction of cyclohexane with $Br_2$ in the presence of $h
u$ ($UV$ light) is a free-radical substitution reaction,which produces bromocyclohexane as product $(A)$.$2$. The reaction of bromocyclohexane with $Na$ in the presence of dry ether is a Wurtz reaction,which involves the coupling of two alkyl groups to form a higher alkane.$3$. Two molecules of bromocyclohexane react with $2Na$ to form bicyclohexyl as product $(B)$.

In the given reaction,product $B$ is:
Cyclohexane $\xrightarrow{Br_2, h\nu}$ $(A) \xrightarrow{Na, \text{dry ether}}$ $(B)$

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In the given reaction,product $B$ is:Cyclohexane $\xrightarrow{Br_2, h\nu}$ $(A) \xrightarrow{Na, \text{dry ether}}$ $(B)$