The product (A) in the following reaction is: | vedclass

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(B) The reaction involves the ring-opening of trimethylene carbonate by excess phenylmagnesium bromide $(PhMgBr)$.$1$. The first equivalent of $PhMgBr

Vedclass · Accepted Answer

$Ph-C(OH)(Ph)_2$

Vedclass · Answer

(B) The reaction involves the ring-opening of trimethylene carbonate by excess phenylmagnesium bromide $(PhMgBr)$.$1$. The first equivalent of $PhMgBr$ attacks the carbonyl carbon of the cyclic carbonate,leading to ring opening and the formation of a benzoate ester intermediate: $Ph-CO-O-CH_2-CH_2-CH_2-OMgBr$.$2$. Subsequent reaction with excess $PhMgBr$ leads to the formation of triphenylmethanol $(Ph_3C-OH)$ after acid hydrolysis.$3$. The final product is triphenylmethanol,which is represented as $Ph-C(OH)(Ph)_2$.

The product $(A)$ in the following reaction is:

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