The reaction sequence is given as follows:Pro | vedclass

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(B) $1$. The starting material is a cyclopropylidene derivative with a bromine atom. Upon treatment with $Mg$ in ether,it forms a Grignard reagent.$2$

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$Ph-C \equiv C-CH_2-CH_2-CH_2-OH$

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(B) $1$. The starting material is a cyclopropylidene derivative with a bromine atom. Upon treatment with $Mg$ in ether,it forms a Grignard reagent.$2$. Due to the high ring strain in the cyclopropane ring,the ring opens to relieve the strain,resulting in the formation of a linear alkyne Grignard reagent: $Ph-C \equiv C-CH_2-CH_2-MgBr$.$3$. This Grignard reagent then reacts with formaldehyde $(HCHO)$ followed by acidic workup $(H^+)$ to form a primary alcohol.$4$. The final product $(B)$ is $Ph-C \equiv C-CH_2-CH_2-CH_2-OH$.

The reaction sequence is given as follows:
Product $(B)$ is:

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The reaction sequence is given as follows:Product $(B)$ is: