Product (A) is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of the given substituted cyclohexane with alcoholic $KOH$ is an $E2$ elimination reaction. For an $E2$ reaction to occur,the leaving

Vedclass · Accepted Answer

Vedclass · Answer

(A) The reaction of the given substituted cyclohexane with alcoholic $KOH$ is an $E2$ elimination reaction. For an $E2$ reaction to occur,the leaving group $(-Br)$ and the $\beta$-hydrogen (or $\beta$-deuterium) must be in an anti-periplanar conformation. In the given chair conformation,the $-Br$ group is in an axial position. The $\beta$-hydrogens and $\beta$-deuterium are also present. Specifically,the $\beta$-deuterium atom is in an anti-periplanar position relative to the axial $-Br$ group. Therefore,the base removes the deuterium atom,leading to the formation of the alkene where the double bond is formed between the carbon bearing the $-Br$ and the carbon bearing the $-D$. The product is $3$-methylcyclohexene.

Product $(A)$ is

Similar Questions

$A$ given mass of gas expands reversibly from the state $A$ to the state $B$ by three paths $1, 2$ and $3$ as shown in the figure. If $w_1, w_2$ and $w_3$ respectively be the work done by the gas along three paths then

In an $LC$ circuit,the capacitor has a maximum charge $q_0$. The value of $\left. \frac{di}{dt} \right|_{\max }$ is:

If the line $x+3y=0$ is the tangent at $(0,0)$ to the circle of radius $1$,then the centre of one such circle is

Which of the following pairs of ions are colourless?

For the given logic gate circuit, which of the following is the correct truth table?

Vedclass Test Series

Exam Paper Generator

Online Exam Module