Product (B) of the above reaction is: | vedclass

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(B) The starting material is a dibromo-epoxide. Treatment with $2 	ext{ moles}$ of $NaOCH_3$ in $CH_3OH$ leads to the elimination of $2 	ext{ moles}

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Phenol

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(B) The starting material is a dibromo-epoxide. Treatment with $2 	ext{ moles}$ of $NaOCH_3$ in $CH_3OH$ leads to the elimination of $2 	ext{ moles}$ of $HBr$ to form an epoxide ring fused to a cyclohexadiene system. Upon treatment with $H_3O^+$,the epoxide ring undergoes acid-catalyzed opening followed by rearrangement to form a more stable aromatic system. The final product $(B)$ is phenol $(C_6H_5OH)$.

Product $(B)$ of the above reaction is:

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