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Question

(A) The reaction involves the electrophilic addition of $Br_2$ to the alkene double bond. $1$. The alkene reacts with $Br_2$ to form a cyclic bromoniu

Vedclass · Accepted Answer

$A$ cyclic ether with a bromomethyl group.

Vedclass · Answer

(A) The reaction involves the electrophilic addition of $Br_2$ to the alkene double bond. $1$. The alkene reacts with $Br_2$ to form a cyclic bromonium ion intermediate. $2$. The internal nucleophilic hydroxyl group $(-OH)$ attacks the more substituted carbon of the bromonium ion,leading to the formation of a cyclic ether (a six-membered ring). $3$. The oxygen atom becomes positively charged,and subsequently,a proton is removed by the bromide ion $(Br^-)$ to form the final product $W$,which is a cyclic ether with a bromomethyl group attached.

Product $W$ is

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