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(C) Step $1$: Dehydration of $2	ext{-methylcyclohexanol}$ with $H^+/\Delta$ gives $1	ext{-methylcyclohexene}$ as the major product $(A)$ due to Sayt

Vedclass · Accepted Answer

$2-$hydroxy$-2-$methylcyclohexanone

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(C) Step $1$: Dehydration of $2	ext{-methylcyclohexanol}$ with $H^+/\Delta$ gives $1	ext{-methylcyclohexene}$ as the major product $(A)$ due to Saytzeff's rule.Step $2$: Syn-hydroxylation of $1	ext{-methylcyclohexene}$ with cold dilute $KMnO_4$ (Baeyer's reagent) yields $1	ext{-methylcyclohexane-1,2-diol}$ as product $(B)$.Step $3$: Oxidation of the secondary alcohol group in $1	ext{-methylcyclohexane-1,2-diol}$ using $CrO_3$ (Jones reagent or similar) selectively oxidizes the secondary alcohol to a ketone,while the tertiary alcohol remains unaffected. Thus,the product $(C)$ is $2	ext{-hydroxy-2-methylcyclohexanone}$.

The reaction sequence is as follows:
$2\text{-methylcyclohexanol}$ $\xrightarrow{H^+, \Delta} (A)$ $\xrightarrow{\text{cold dil. } KMnO_4} (B)$ $\xrightarrow{CrO_3} (C)$
Identify the product $(C)$.

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The reaction sequence is as follows:$2\text{-methylcyclohexanol}$ $\xrightarrow{H^+, \Delta} (A)$ $\xrightarrow{\text{cold dil. } KMnO_4} (B)$ $\xrightarrow{CrO_3} (C)$Identify the product $(C)$.