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(D) The reaction involves the protonation of the hydroxyl group by $HCl$,followed by the loss of water to form a carbocation. This carbocation undergo

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(D) The reaction involves the protonation of the hydroxyl group by $HCl$,followed by the loss of water to form a carbocation. This carbocation undergoes an intramolecular electrophilic addition to the double bond,leading to a bicyclic system. Finally,the chloride ion attacks the resulting carbocation to form the major product. The reaction sequence is as follows: $1$. Protonation of $-OH$ group: The $-OH$ group is protonated by $HCl$ to form $-OH_2^+$.$2$. Formation of carbocation: Water is eliminated to form a carbocation at the allylic position.$3$. Cyclization: The double bond attacks the carbocation,leading to the formation of a bicyclic carbocation.$4$. Nucleophilic attack: The $Cl^-$ ion attacks the carbocation to yield the final product,which is a substituted bicyclic compound.

The product $(P)$ is:

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