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(C) $1$. Cyclohexanecarboxylic acid reacts with $LiH$ in dimethoxyethane to form the lithium salt of the acid,$(L)$,which is cyclohexanecarboxylate li

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Cyclohexanecarboxylic acid

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(C) $1$. Cyclohexanecarboxylic acid reacts with $LiH$ in dimethoxyethane to form the lithium salt of the acid,$(L)$,which is cyclohexanecarboxylate lithium,$C_6H_{11}COOLi$.$2$. The lithium salt $(L)$ then reacts with methyllithium $(CH_3Li)$. However,the carboxylate salt is generally unreactive towards nucleophilic attack by organolithium reagents under these conditions,or it forms a stable intermediate $(M)$ which is the methyl ester,$C_6H_{11}COOCH_3$,upon workup or specific reaction conditions.$3$. The final step is the hydrolysis of $(M)$ with $H_3O^+$. The hydrolysis of the ester $C_6H_{11}COOCH_3$ yields the original carboxylic acid,cyclohexanecarboxylic acid $(N)$,and methanol $(CH_3OH)$.$4$. Therefore,the product $(N)$ is cyclohexanecarboxylic acid.

The product $(N)$ is

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