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(A) $1$. The reaction of cyclopentanone with phenylmagnesium bromide $(PhMgBr)$ followed by hydrolysis with $NH_4Cl/H_2O$ yields $1-$phenylcyclopentan

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$1-$phenylcyclopentene

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(A) $1$. The reaction of cyclopentanone with phenylmagnesium bromide $(PhMgBr)$ followed by hydrolysis with $NH_4Cl/H_2O$ yields $1-$phenylcyclopentanol $(O)$.$2$. Treatment of $1-$phenylcyclopentanol with cold concentrated $HCl$ results in the substitution of the $-OH$ group with a $-Cl$ atom,forming $1-$chloro$-1-$phenylcyclopentane $(P)$.$3$. Finally,the reaction of $1-$chloro$-1-$phenylcyclopentane with $KOH$ in ethanol under heating (dehydrohalogenation) leads to the formation of $1-$phenylcyclopentene $(Q)$ via an $E2$ elimination mechanism.

The product $(Q)$ will be:

Similar Questions

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