The product (B) in the given reaction is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The reaction of cyclohexylideneacetic acid with excess $CH_3Li$ followed by $HCl/H_2O$ converts the carboxylic acid group into a methyl keton

Vedclass · Accepted Answer

Sodium cyclohex$-1-$ene$-1-$carboxylate

Vedclass · Answer

(C) $1$. The reaction of cyclohexylideneacetic acid with excess $CH_3Li$ followed by $HCl/H_2O$ converts the carboxylic acid group into a methyl ketone,forming cyclohexylideneacetone $(A)$.$2$. The compound $(A)$ contains a methyl ketone group $(CH_3-CO-)$,which undergoes the haloform reaction with $I_2/NaOH$.$3$. The haloform reaction cleaves the methyl ketone to form a carboxylate salt and iodoform $(CHI_3)$.$4$. The product $(B)$ is sodium cyclohex$-1-$ene$-1-$carboxylate.

The product $(B)$ in the given reaction is:

Similar Questions

$HCHO$ (more reactive towards oxidation) + $CH_3CHO \xrightarrow{Conc. NaOH}$ Find out the products of the reaction.

The major product of the following reaction is:

The major product formed in the following reaction is
(Structure of the reactant) $\xrightarrow[{CHCl_3}]{{PCC}}$

$CH_3CHO$ reacts with aqueous $NaOH$ solution to form

Predict the products of the following reactions with $CH_3CHO$:
$(i) CH_3CHO + C_6H_5MgBr$
$(ii) CH_3CHO + C_6H_{11}MgBr$
$(iii) CH_3CHO + (CH_3)_2CHMgBr$
Followed by acidic hydrolysis in each case.

Vedclass Test Series

Exam Paper Generator

Online Exam Module