Identify the product (C) in the following rea | vedclass

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(C) $1$. The starting material is a $\beta$-halo carboxylate. Upon decarboxylation $(-CO_2)$,it forms an alkene: $CH_3-CH(Cl)-CH(Cl)-COO^- \rightarrow

Vedclass · Accepted Answer

$CH_3-CH_2-CHO$

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(C) $1$. The starting material is a $\beta$-halo carboxylate. Upon decarboxylation $(-CO_2)$,it forms an alkene: $CH_3-CH(Cl)-CH(Cl)-COO^- \rightarrow CH_3-CH=CH-Cl$ (Product $A$).$2$. Addition of $HCl$ to $A$ follows Markovnikov's rule: $CH_3-CH=CH-Cl + HCl \rightarrow CH_3-CH_2-CH(Cl)_2$ (Product $B$,a gem-dichloride).$3$. Hydrolysis of the gem-dichloride with aqueous $KOH$ replaces the chlorine atoms with hydroxyl groups,which are unstable on the same carbon and eliminate water to form an aldehyde: $CH_3-CH_2-CH(Cl)_2 + 2KOH(aq)$ $\rightarrow CH_3-CH_2-CH(OH)_2$ $\rightarrow CH_3-CH_2-CHO + H_2O$ (Product $C$).

Identify the product $(C)$ in the following reaction sequence:
$CH_3-CH(Cl)-CH(Cl)-COO^-$ $\xrightarrow{-CO_2} A$ $\xrightarrow{HCl} B$ $\xrightarrow{aq. KOH} C$

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Identify the product $(C)$ in the following reaction sequence:$CH_3-CH(Cl)-CH(Cl)-COO^-$ $\xrightarrow{-CO_2} A$ $\xrightarrow{HCl} B$ $\xrightarrow{aq. KOH} C$