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How will you prepare the following compounds from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom:
$(i)$ Methyl benzoate
$(ii)$ $m$-Nitrobenzoic acid
$(iii)$ $p$-Nitrobenzoic acid
$(iv)$ Phenylacetic acid
$(v)$ $p$-Nitrobenzaldehyde.

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In the given reaction $[X]$ will be :

$CH_3-C(=O)-OH$ $\xrightarrow{NaH^{14}CO_3} (A) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (B)$
$CH_3-S(=O)_2-OH$ $\xrightarrow{NaH^{14}CO_3} (C) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (D)$
Product $(B)$ and $(D)$ in the above reaction are:

Arrange the following compounds in increasing order of their property as indicated:
$(i)$ Acetaldehyde,Acetone,Di-tert-butyl ketone,Methyl tert-butyl ketone (reactivity towards $HCN$)
$(ii)$ $CH_3CH_2CH(Br)COOH$,$CH_3CH(Br)CH_2COOH$,$(CH_3)_2CHCOOH$,$CH_3CH_2CH_2COOH$ (acid strength)
$(iii)$ Benzoic acid,$4$-Nitrobenzoic acid,$3,4$-Dinitrobenzoic acid,$4$-Methoxybenzoic acid (acid strength)

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How many products will be formed when the given compound undergoes decarboxylation?

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