The reaction is given as:Naphthalene + Oxalyl | vedclass

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(C) $1$. The reaction of naphthalene with oxalyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts acylation reaction.$2$. This reaction leads

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Acenaphthene

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(C) $1$. The reaction of naphthalene with oxalyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts acylation reaction.$2$. This reaction leads to the formation of acenaphthenequinone,which is the intermediate $[X]$.$3$. The subsequent reduction of the carbonyl groups in $[X]$ using $Na-Hg$ and $HCl$ (Clemmensen reduction) converts the two ketone groups into methylene groups $(-CH_2-)$.$4$. This reduction process yields acenaphthene as the final product $[Y]$.

The reaction is given as:
Naphthalene + Oxalyl chloride $\xrightarrow{AlCl_3} [X]$ $\xrightarrow{Na-Hg, HCl \text{ (excess)}} [Y]$
Product $Y$ is:

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The reaction is given as:Naphthalene + Oxalyl chloride $\xrightarrow{AlCl_3} [X]$ $\xrightarrow{Na-Hg, HCl \text{ (excess)}} [Y]$Product $Y$ is: