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(D) Step $1$: Electrophilic aromatic substitution $(Br_2, Fe)$ on ethylbenzene gives $p$-bromoethylbenzene as the major product due to the ortho/para

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$1-$bromo$-4-$ethenylbenzene

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(D) Step $1$: Electrophilic aromatic substitution $(Br_2, Fe)$ on ethylbenzene gives $p$-bromoethylbenzene as the major product due to the ortho/para directing nature of the ethyl group.Step $2$: Benzylic halogenation $(Cl_2, \Delta)$ occurs at the benzylic position of the ethyl group,yielding $1-(4-bromophenyl)-1-chloroethane$.Step $3$: Dehydrohalogenation using $alc. KOH$ (elimination reaction) removes $HCl$ from the side chain to form the alkene,resulting in $1-bromo-4-ethenylbenzene$ (also known as $p$-bromostyrene).

The product $A$ of the following sequence of reactions is:
Ethylbenzene $\xrightarrow[(b) Cl_2, \Delta]{(a) Br_2, Fe}$ $\xrightarrow{(c) alc. KOH} 'A' \text{ (Major product)}$

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The product $A$ of the following sequence of reactions is:Ethylbenzene $\xrightarrow[(b) Cl_2, \Delta]{(a) Br_2, Fe}$ $\xrightarrow{(c) alc. KOH} 'A' \text{ (Major product)}$