The products (A) and (B) respectively in the | vedclass

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Question

(C) In the Beckmann rearrangement,the group anti to the $-OH$ group migrates to the nitrogen atom.For the first reactant,the $Ph$ group is anti to the

Vedclass · Accepted Answer

$Ph-C(=O)-NH-CH_3, CH_3-C(=O)-NH-Ph$

Vedclass · Answer

(C) In the Beckmann rearrangement,the group anti to the $-OH$ group migrates to the nitrogen atom.For the first reactant,the $Ph$ group is anti to the $-OH$ group,so it migrates to form $Ph-C(=O)-NH-CH_3$ as product $(A)$.For the second reactant,the $CH_3$ group is anti to the $-OH$ group,so it migrates to form $CH_3-C(=O)-NH-Ph$ as product $(B)$.Thus,the correct option is $(C)$.

The products $(A)$ and $(B)$ respectively in the above reaction are:

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