The product of the given reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is an $S_NAr$ (nucleophilic aromatic substitution) reaction. The $-NO_2$ group is a strong electron-withdrawing group that activates

Vedclass · Accepted Answer

$4-$bromo$-2-$nitrophenol

Vedclass · Answer

(A) The reaction is an $S_NAr$ (nucleophilic aromatic substitution) reaction. The $-NO_2$ group is a strong electron-withdrawing group that activates the ortho and para positions towards nucleophilic attack. In $1-bromo-4-bromo-2-nitrobenzene$ (or $1,4-dibromo-2-nitrobenzene$),the bromine atom at the para position relative to the $-NO_2$ group is more susceptible to nucleophilic substitution by $HO^-$ due to the resonance stabilization of the Meisenheimer complex intermediate. Therefore,the $HO^-$ group replaces the para-bromine atom to form $4-bromo-2-nitrophenol$.

Similar Questions

What are $Y$ and $Z$ respectively in the following reaction sequence?
Chlorobenzene $\xrightarrow[Conc. H_2SO_4]{HNO_3}$ $X$ (major product) $\xrightarrow{Y}$ $Z$

Number of deactivating groups in the following is $-Cl, -SO_3H, -OH, -NHC_2H_5, -COOCH_3, -CH_3$.

The Fittig reaction is:

Which of the following compounds will have the highest melting point and why?

Heating chlorobenzene with $NaOH$ at $300\,^oC$ under pressure yields ...........

Vedclass Test Series

Exam Paper Generator

Online Exam Module