The product of the reaction is:

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(B) The given reactant is a diol containing a primary alcohol $(-CH_2OH)$ and a tertiary alcohol $(-C(OH)(CH_3)_2)$.Pyridinium chlorochromate $(PCC)$

Vedclass · Accepted Answer

$4-$($2$-hydroxypropan$-2-$yl)cyclohexanecarbaldehyde

Vedclass · Answer

(B) The given reactant is a diol containing a primary alcohol $(-CH_2OH)$ and a tertiary alcohol $(-C(OH)(CH_3)_2)$.Pyridinium chlorochromate $(PCC)$ is a selective oxidizing agent that oxidizes primary alcohols to aldehydes and secondary alcohols to ketones.It does not oxidize tertiary alcohols.Therefore,the primary alcohol group is oxidized to an aldehyde group $(-CHO)$,while the tertiary alcohol group remains unchanged.The product is $4-(2-hydroxypropan-2-yl)cyclohexanecarbaldehyde$.

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