The product of the reaction is:

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Question

(C) The starting material is a $1,1$-dicarboxylic acid derivative of a cyclopentane ring. Upon heating,geminal dicarboxylic acids undergo decarboxylat

Vedclass · Accepted Answer

Both $(a)$ and $(b)$

Vedclass · Answer

(C) The starting material is a $1,1$-dicarboxylic acid derivative of a cyclopentane ring. Upon heating,geminal dicarboxylic acids undergo decarboxylation,where one of the $-CO_2H$ groups is lost as $CO_2$. Since the starting material has two $-CO_2H$ groups at the same carbon,the decarboxylation can occur by losing either of the two groups. Because the molecule has stereocenters at the positions of the methyl groups,the loss of the two different $-CO_2H$ groups leads to the formation of two different stereoisomers (diastereomers) of the resulting monocarboxylic acid. Therefore,both products shown in options $(a)$ and $(b)$ are formed.

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In the given reaction :
$CH_3-COOH$ $\mathop{\xrightarrow{(i) Br_2/P}}_{(ii) NaCN, (iii) H_2O/H^{+}/\Delta}$ $[X]$
$[X]$ will be :

Which of the following acids has the lowest $pK_a$ value?

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