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(A) The starting material is $1,3$-benzodioxole. Step $(i)$: Treatment with excess $HI$ causes the cleavage of the cyclic acetal (dioxole ring). The $

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(A) The starting material is $1,3$-benzodioxole. Step $(i)$: Treatment with excess $HI$ causes the cleavage of the cyclic acetal (dioxole ring). The $C-O$ bonds are broken,resulting in the formation of a catechol derivative ($1,2$-dihydroxybenzene) and formaldehyde $(CH_2O)$,but in this specific fused system,the ring opening leads to $2$-hydroxybenzyl alcohol (salicyl alcohol). Step $(ii)$: The Reimer-Tiemann reaction $(CHCl_3, NaOH)$ introduces a formyl group $(-CHO)$ at the ortho position relative to the phenolic $-OH$ group. Thus,the product is $2$-hydroxy$-3-$(hydroxymethyl)benzaldehyde.

Column $I$	Column $II$
$A$. $C_6H_5CHO$	$p$. gives precipitate with $2, 4-$dinitrophenylhydrazine
$B$. $CH_3C \equiv CH$	$q$. gives precipitate with $AgNO_3$
$C$. $CN^{-}$	$r$. is a nucleophile
$D$. $I^{-}$	$s$. is involved in cyanohydrin formation

Predict the major product of the following reaction:
$1,3$-benzodioxole $\xrightarrow[(ii) CHCl_3, NaOH]{(i) HI \text{ (excess)}}$ ?

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Predict the major product of the following reaction:$1,3$-benzodioxole $\xrightarrow[(ii) CHCl_3, NaOH]{(i) HI \text{ (excess)}}$ ?