Propyne on reaction with water in the presenc | vedclass

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(C) Step $1$: The reaction of an alkyne with water in the presence of dilute $H_2SO_4$ and $HgSO_4$ is known as Kucherov's reaction.Step $2$: Propyne

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Propanone

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(C) Step $1$: The reaction of an alkyne with water in the presence of dilute $H_2SO_4$ and $HgSO_4$ is known as Kucherov's reaction.Step $2$: Propyne $(CH_3-C \equiv CH)$ undergoes hydration following Markovnikov's rule.Step $3$: The addition of $H_2O$ across the triple bond forms an unstable enol intermediate: $CH_3-C(OH)=CH_2$.Step $4$: This enol undergoes tautomerization to form a stable ketone, which is Propanone $(CH_3-CO-CH_3)$.

Propyne on reaction with water in the presence of $40\% \ \text{H}_2\text{SO}_4$ and $1\% \ \text{HgSO}_4$ forms:

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