Propyne reacts with excess HBr to form the co | vedclass

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(D) The reaction of propyne $(CH_3-C \equiv CH)$ with excess $HBr$ follows Markovnikov's rule.In the first step,$HBr$ adds across the triple bond to f

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$CH_3CBr_2CH_3$

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(D) The reaction of propyne $(CH_3-C \equiv CH)$ with excess $HBr$ follows Markovnikov's rule.In the first step,$HBr$ adds across the triple bond to form $2-$bromopropene $(CH_3-C(Br)=CH_2)$.In the second step,another molecule of $HBr$ adds to the alkene following Markovnikov's rule,where the hydrogen atom attaches to the carbon with more hydrogens and the bromine atom attaches to the more substituted carbon.This results in the formation of $2,2-$dibromopropane $(CH_3-CBr_2-CH_3)$.

Propyne reacts with excess $HBr$ to form the compound $Z$. The structure of $Z$ is:

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